* Added workaround so at least interactive python detection works

(although not perfectly) in python <= 2.5.
master
Wirawan Purwanto 13 years ago
parent f8a101fbe9
commit 1674bfd256
  1. 10
      interactive_tools.py

@ -64,15 +64,23 @@ def detect_interactive(global_ns=None):
* For ipython, see if "__IPYTHON__" is defined in the user's global
namespace.
* For "python -i" invocation, sys.flags.interactive will be set to True.
(python 2.6+ only)
* For vanilla "python" invocation with no argument, then sys.ps1
variable exists.
"""
def is_python_i():
# This approach only works for Python 2.6+
try:
return sys.flags.interactive
except:
return False
(g, b) = get_global_namespace_(global_ns)
if "__IPYTHON__" in g or hasattr(b, "__IPYTHON__"):
return {
'session': 'ipython',
}
elif sys.flags.interactive:
elif is_python_i(): # sys.flags.interactive:
return {
'session': 'python -i',
}

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